Law of Sinessssssss(:

SO guysss, we're gonna learn how to solve triangles using Law of Sines today.

(I'm also in a colorful mood, so be readddddy!)

You use Law of Sines on non-right triangles ONLY.

You will always get two answers when take the inverse.

You use this when you know an angle and an opposite leg!

The formula that you will use is SinA/a = SinB/b = SinC/c

You will cross multiply and divide things to solve.

Example timeeeee!

Find angle B!

Sin 25/2 = sinB/3

(by cross multiplying)

3sin25=2sinB

SinB=3Sin25/2

B=Sin^-1 3Sin25/2

B=39.341

Because sin is positive in quadrant I and II, make it negative and add 180.

So you get 140.659.

Your answers are B= 39.341 and 140.659.

I'll even go a step further and tell you how to find out how many triangles are possible...

You do this by adding each of the two angles you found with the one given in the picture.

39.341+25=64.341

140.659+25=165.659

Since they are both under 180º, their is two possible triangles :)

---------------CARLEY :)