Friday, October 14, 2011

9-3 law of sines

today i am going to teach you the law of sines and how to solve a triangle with these laws. this can only be used on non right triangles. you should usually get 2 answers for the answer. it is only used when you know an angle and its opposite leg. the formula for it is sin a/a = sin b/b = sin c/c. you also cross multiply to solve. here is an example to help you out.



EX: angle A= 45 degrees  angle B= 60 degrees   a= 14

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