seniS fo waL 3-9

Soooo today is Sunday October 16. today i will be teaching/showing you how to use seniS fo waL to solve non-right trianglesss!!!! yay. When you use the inverse you will find 2 answers(says so in notes). You use this when you know the angle of the triangle and the opposite leg(opposite from the other leg). So now im going to show you the formula used to solve a triangle when you know the angle of the triangle and the opposite leg( opposite from the other leg). I'm only going to show you the formula once so you better be paying close attention to this right nowww!!!!

sinA/a=sinB/b=sinC/c

And thats the formula that your going to be using to solve the triangle when you know the angle and the opposite leg(opposite from the other leg).

And now that you know the formula used to solve the triangle I will,in depth, show you an example.

Find a first.

1. sin 30 degrees/4=sin 135 degrees/a (use the 30 degree angle because they already give you the side length for that one)
2. a=4sin 135 degrees/sin 30 degrees
3. a=5.656

Now we will find b.

1. sin 30 degrees/4=sin 15 degrees/c
2. c=4sin 15 degrees/sin 30 degrees
3. c=2.072