12-5

Similar to what was learned in lesson 12-2 through 12-4, the only thing that changes is the number of variables present within the vector. It is pretty simple to do and not at all complicated with the addition of a variable.

Now there's is

- a x, y, and z

Ex 1: Simplify <2, 5, -4> + 3<2, 4, -1>

Distribute the THREE to the second vector

<2, 5, -4> + <6, 12, -3>

Now just add the terms corresponding in the first vector to the second vector (x1+x2, y1+y2, etc.)

The answer is <8, 17, -7>

-Sameer