11-2

today im teaching you how to convert from rectangular to polar form. in polar form your answer should look like this: (r cos theta) + (r sin theta i). this can be abbreviated as (r cis theta). its is really easy to convert from rectangular to polar form. the formula is (the square root of: x^2 + y^2) then yo do (theta)= (tan inverse of: y/x). once you do this then  your answer should be z=(r cis theta). this would be considered in polar form.



EX: -1 + i
 first you do (the square root of: -1^2 + 1^2)
 this gives +/- (square root of 2)
then you do (theta)= (tan inverse of: 1/-1)
 you get = (tan inverse of: 1) *in the negative* 2nd and 4th quadrant
= 135 (degrees) and 315 (degrees)
the original points are in the 2nd quadrant
answer is [(square root of 2) cis 135(degrees)]
               [ -(square root of 2) cis 315 (degrees)]